Thompson order formula

Statement

If a finite group G has exactly two conjugacy classes of involutions with representatives t and z, then the Thompson order formula states

: |G| = |C_g(z)| a(t) + |C_g(t)| a(z) Here a(x) is the number of pairs (u,v) with u conjugate to t, v conjugate to z, and x in the subgroup generated by uv.

gives the following more complicated version of the Thompson order formula for the case when G has more than two conjugacy classes of involution. :|G| = C_G(t)C_G(z) \sum_x\frac{a(x)}{C_G(x)} where t and z are non-conjugate involutions, the sum is over a set of representatives x for the conjugacy classes of involutions, and a(x) is the number of ordered pairs of involutions u,v such that u is conjugate to t, v is conjugate to z, and x is the involution in the subgroup generated by tz.

Proof

The Thompson order formula can be rewritten as

:\frac{|G|}{C_G(z)}\frac{|G|}{C_G(t)} = \sum_x a(x)\frac{|G|}{C_G(x)}

where as before the sum is over a set of representatives x for the classes of involutions. The left hand side is the number of pairs on involutions (u,v) with u conjugate to t, v conjugate to z. The right hand side counts these pairs in classes, depending the class of the involution in the cyclic group generated by uv. The key point is that uv has even order (as if it had odd order then u and v would be conjugate) and so the group it generates contains a unique involution x.

References