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Kemeny method
Single-winner electoral system
Single-winner electoral system
The Kemeny method is an electoral system that uses ranked ballots and pairwise comparison counts to identify the most popular choices in an election. It is a Condorcet method because if there is a Condorcet winner, it will always be ranked as the most popular choice.
This method assigns a score for each possible sequence, where each sequence considers which choice might be most popular, which choice might be second-most popular, which choice might be third-most popular, and so on down to which choice might be least-popular. The sequence that has the highest score is the winning sequence, and the first choice in the winning sequence is the most popular choice. (As explained below, ties can occur at any ranking level.)
The Kemeny method is also known as the Kemeny-Young rule, VoteFair popularity ranking, the maximum likelihood method, and the median relation.
Description
The Kemeny method uses preferential ballots on which voters rank choices according to their order of preference. A voter is allowed to rank more than one choice at the same preference level. Unranked choices are usually interpreted as least-preferred.
Kemeny calculations are usually done in two steps. The first step is to create a matrix or table that counts pairwise voter preferences. The second step is to test all possible rankings, calculate a score for each such ranking, and compare the scores. Each ranking score equals the sum of the pairwise counts that apply to that ranking.
The ranking that has the largest score is identified as the overall ranking. (If more than one ranking has the same largest score, all these possible rankings are tied, and typically the overall ranking involves one or more ties.)
Another way to view the ordering is that it is the one which minimizes the sum of the Kendall tau distances (bubble sort distance) to the voters' lists.
In order to demonstrate how an individual preference order is converted into a tally table, it is worth considering the following example. Suppose that a single voter has a choice among four candidates (i.e. Elliot, Meredith, Roland, and Selden) and has the following preference order:
| Preference | |
|---|---|
| order | Choice |
| First | Elliot |
| Second | Roland |
| Third | Meredith or Selden |
| (equal preference) |
These preferences can be expressed in a tally table. A tally table, which arranges all the pairwise counts in three columns, is useful for counting (tallying) ballot preferences and calculating ranking scores. The center column tracks when a voter indicates more than one choice at the same preference level. The above preference order can be expressed as the following tally table:
| All possible pairs | ||||
|---|---|---|---|---|
| of choice names | Number of votes with indicated preference | Prefer X over Y | Equal preference | Prefer Y over X |
| X = Selden | ||||
| Y = Meredith | 0 | +1 vote | 0 | |
| X = Selden | ||||
| Y = Elliot | 0 | 0 | +1 vote | |
| X = Selden | ||||
| Y = Roland | 0 | 0 | +1 vote | |
| X = Meredith | ||||
| Y = Elliot | 0 | 0 | +1 vote | |
| X = Meredith | ||||
| Y = Roland | 0 | 0 | +1 vote | |
| X = Elliot | ||||
| Y = Roland | +1 vote | 0 | 0 |
Now suppose that multiple voters had voted on those four candidates. After all ballots have been counted, the same type of tally table can be used to summarize all the preferences of all the voters. Here is an example for a case that has 100 voters:
| All possible pairs | ||||
|---|---|---|---|---|
| of choice names | Number of votes with indicated preference | Prefer X over Y | Equal preference | Prefer Y over X |
| X = Selden | ||||
| Y = Meredith | 50 | 10 | 40 | |
| X = Selden | ||||
| Y = Elliot | 40 | 0 | 60 | |
| X = Selden | ||||
| Y = Roland | 40 | 0 | 60 | |
| X = Meredith | ||||
| Y = Elliot | 40 | 0 | 60 | |
| X = Meredith | ||||
| Y = Roland | 30 | 0 | 70 | |
| X = Elliot | ||||
| Y = Roland | 30 | 0 | 70 |
The sum of the counts in each row must equal the total number of votes.
After the tally table has been completed, each possible ranking of choices is examined in turn, and its ranking score is calculated by adding the appropriate number from each row of the tally table. For example, the possible ranking:
- Elliot
- Roland
- Meredith
- Selden satisfies the preferences Elliot Roland, Elliot Meredith, Elliot Selden, Roland Meredith, Roland Selden, and Meredith Selden. The respective scores, taken from the table, are
- Elliot Roland: 30
- Elliot Meredith: 60
- Elliot Selden: 60
- Roland Meredith: 70
- Roland Selden: 60
- Meredith Selden: 40 giving a total ranking score of 30 + 60 + 60 + 70 + 60 + 40 = 320.
Calculating the overall ranking
After the scores for every possible ranking have been calculated, the ranking that has the largest score can be identified, and becomes the overall ranking. In this case, the overall ranking is:
- Roland
- Elliot
- Selden
- Meredith with a ranking score of 370.
If there are cycles or ties, more than one possible ranking can have the same largest score. Cycles are resolved by producing a single overall ranking where some of the choices are tied.
Summary matrix
After the overall ranking has been calculated, the pairwise comparison counts can be arranged in a summary matrix, as shown below, in which the choices appear in the winning order from most popular (top and left) to least popular (bottom and right). This matrix layout does not include the equal-preference pairwise counts that appear in the tally table:
| Prefer **Meredith** ... | 30 | 40 | 40 | - |
|---|
In this summary matrix, the largest ranking score equals the sum of the counts in the upper-right, triangular half of the matrix (shown here in bold, with a green background). No other possible ranking can have a summary matrix that yields a higher sum of numbers in the upper-right, triangular half. (If it did, that would be the overall ranking.)
In this summary matrix, the sum of the numbers in the lower-left, triangular half of the matrix (shown here with a red background) are a minimum. The academic papers by John Kemeny and Peyton Young refer to finding this minimum sum, which is called the Kemeny score, and which is based on how many voters oppose (rather than support) each pairwise order:
| Method | First-place winner |
|---|---|
| Kemeny | Roland |
| Condorcet | Roland |
| Instant runoff voting | Elliot or Selden |
| (depending on how the second-round tie is handled) | |
| Plurality | Selden |
Example
This matrix summarizes the corresponding pairwise comparison counts:
| Prefer | ||||
|---|---|---|---|---|
| **Knoxville** ... | 58% | 32% | 17% | - |
The Kemeny method arranges the pairwise comparison counts in the following tally table:
| All possible pairs | ||||
|---|---|---|---|---|
| of choice names | Number of votes with indicated preference | Prefer X over Y | Equal preference | Prefer Y over X |
| X = Memphis | ||||
| Y = Nashville | 42% | 0 | 58% | |
| X = Memphis | ||||
| Y = Chattanooga | 42% | 0 | 58% | |
| X = Memphis | ||||
| Y = Knoxville | 42% | 0 | 58% | |
| X = Nashville | ||||
| Y = Chattanooga | 68% | 0 | 32% | |
| X = Nashville | ||||
| Y = Knoxville | 68% | 0 | 32% | |
| X = Chattanooga | ||||
| Y = Knoxville | 83% | 0 | 17% |
The ranking score for the possible ranking of Memphis first, Nashville second, Chattanooga third, and Knoxville fourth equals (the unit-less number) 345, which is the sum of the following annotated numbers.
:42% (of the voters) prefer Memphis over Nashville :42% prefer Memphis over Chattanooga :42% prefer Memphis over Knoxville :68% prefer Nashville over Chattanooga :68% prefer Nashville over Knoxville :83% prefer Chattanooga over Knoxville
This table lists all the ranking scores:
| First | ||
|---|---|---|
| choice | Second | |
| choice | Third | |
| choice | Fourth | |
| choice | Ranking | |
| score | ||
| Memphis | ||
| Memphis | ||
| Memphis | ||
| Memphis | ||
| Memphis | ||
| Memphis | ||
| Nashville | ||
| Nashville | ||
| Nashville | ||
| Nashville | ||
| Nashville | ||
| Nashville | ||
| Chattanooga | ||
| Chattanooga | ||
| Chattanooga | ||
| Chattanooga | ||
| Chattanooga | ||
| Chattanooga | ||
| Knoxville | ||
| Knoxville | ||
| Knoxville | ||
| Knoxville | ||
| Knoxville | ||
| Knoxville |
The largest ranking score is 393, and this score is associated with the following possible ranking, so this ranking is also the overall ranking:
| Preference | |
|---|---|
| order | Choice |
| First | Nashville |
| Second | Chattanooga |
| Third | Knoxville |
| Fourth | Memphis |
If a single winner is needed, the first choice, Nashville, is chosen. (In this example Nashville is the Condorcet winner.)
The summary matrix below arranges the pairwise counts in order from most popular (top and left) to least popular (bottom and right):
| Prefer **Memphis** ... | 42% | 42% | 42% | - |
|---|
In this arrangement the largest ranking score (393) equals the sum of the counts in bold, which are in the upper-right, triangular half of the matrix (with a green background).
Characteristics
In all cases that do not result in an exact tie, the Kemeny method identifies a most-popular choice, second-most popular choice, and so on.
A tie can occur at any preference level. Except in some cases where circular ambiguities are involved, the Kemeny method only produces a tie at a preference level when the number of voters with one preference exactly matches the number of voters with the opposite preference.
Satisfied criteria for all Condorcet methods
All Condorcet methods, including the Kemeny method, satisfy these criteria:
:;Non-imposition
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