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2011 Internationaux de Strasbourg – Doubles

TPE Chuang Chia-jung CZE Vladimíra Uhlířová

Main article: 2011 Internationaux de Strasbourg

Alizé Cornet and Vania King were the defending champions; however, King decided not to participate.

Cornet plays alongside Anna-Lena Grönefeld but were eliminated in the quarterfinals.

No.4 seeds Akgul Amanmuradova and Chuang Chia-jung defeated No.2 seeds Natalie Grandin and Vladimíra Uhlířová in the final 6–4, 5–7, [10–2] to win the title.

Seeds

CZE Lucie Hradecká / IND Sania Mirza (first round)
RSA Natalie Grandin / CZE Vladimíra Uhlířová (final)
RUS Alla Kudryavtseva / GER Jasmin Wöhr (first round)
UZB Akgul Amanmuradova / TPE Chuang Chia-jung (champions)

Draw

Draw

| RD1-seed01=1 | RD1-team01=CZE L Hradecká IND S Mirza | RD1-score01-1=7 | RD1-score01-2=2 | RD1-score01-3=[10] | RD1-seed02= | RD1-team02=GER A Kerber POL K Piter | RD1-score02-1=5 | RD1-score02-2=6 | RD1-score02-3=[12]

| RD1-seed03= | RD1-team03=FRA K Mladenovic FRA P Parmentier | RD1-score03-1=6 | RD1-score03-2=6 | RD1-score03-3= | RD1-seed04= | RD1-team04=USA G Brodsky CHN W Liu | RD1-score04-1=4 | RD1-score04-2=2 | RD1-score04-3=

| RD1-seed05=4 | RD1-team05=UZB A Amanmuradova TPE C-j Chuang | RD1-score05-1=6 | RD1-score05-2=7 | RD1-score05-3= | RD1-seed06=WC | RD1-team06=BUL D Evtimova FRA V Muntean | RD1-score06-1=0 | RD1-score06-2=5 | RD1-score06-3=

| RD1-seed07= | RD1-team07=CHN S-N Sun CHN Y-F Xu | RD1-score07-1=0 | RD1-score07-2=4 | RD1-score07-3= | RD1-seed08= | RD1-team08=FRA A Cornet GER A-L Grönefeld | RD1-score08-1=6 | RD1-score08-2=6 | RD1-score08-3=

| RD1-seed09= | RD1-team09=FRA S Foretz Gacon FRA A Védy | RD1-score09-1=1 | RD1-score09-2=4 | RD1-score09-3= | RD1-seed10= | RD1-team10=USA M Oudin CHN S Zhang | RD1-score10-1=6 | RD1-score10-2=6 | RD1-score10-3=

| RD1-seed11= | RD1-team11=GER K Barrois SWE J Larsson | RD1-score11-1=6 | RD1-score11-2=6 | RD1-score11-3= | RD1-seed12=3 | RD1-team12=RUS A Kudryavtseva GER J Wöhr | RD1-score12-1=4 | RD1-score12-2=4 | RD1-score12-3=

| RD1-seed13= | RD1-team13=CRO M Lučić USA M Washington | RD1-score13-1=6 | RD1-score13-2=5 | RD1-score13-3=[7] | RD1-seed14= | RD1-team14=AUS D Dominikovic AUS J Moore | RD1-score14-1=2 | RD1-score14-2=7 | RD1-score14-3=[10]

| RD1-seed15= | RD1-team15=CZE H Birnerová USA A Rolle | RD1-score15-1=1 | RD1-score15-2=5 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=RSA N Grandin CZE V Uhlířová | RD1-score16-1=6 | RD1-score16-2=7 | RD1-score16-3=

| RD2-seed01= | RD2-team01=GER A Kerber POL K Piter | RD2-score01-1=5 | RD2-score01-2=4 | RD2-score01-3= | RD2-seed02= | RD2-team02=FRA K Mladenovic FRA P Parmentier | RD2-score02-1=7 | RD2-score02-2=6 | RD2-score02-3=

| RD2-seed03=4 | RD2-team03=UZB A Amanmuradova TPE C-j Chuang | RD2-score03-1=6 | RD2-score03-2=7 | RD2-score03-3= | RD2-seed04= | RD2-team04=FRA A Cornet GER A-L Grönefeld | RD2-score04-1=3 | RD2-score04-2=64 | RD2-score04-3=

| RD2-seed05= | RD2-team05=USA M Oudin CHN S Zhang | RD2-score05-1=6 | RD2-score05-2=2 | RD2-score05-3=[10] | RD2-seed06= | RD2-team06=GER K Barrois SWE J Larsson | RD2-score06-1=4 | RD2-score06-2=6 | RD2-score06-3=[6]

| RD2-seed07= | RD2-team07=AUS D Dominikovic AUS J Moore | RD2-score07-1=3 | RD2-score07-2=2 | RD2-score07-3= | RD2-seed08=2 | RD2-team08=RSA N Grandin CZE V Uhlířová | RD2-score08-1=6 | RD2-score08-2=6 | RD2-score08-3=

| RD3-seed01= | RD3-team01=FRA K Mladenovic FRA P Parmentier | RD3-score01-1=3 | RD3-score01-2=4 | RD3-score01-3= | RD3-seed02=4 | RD3-team02=UZB A Amanmuradova TPE C-j Chuang | RD3-score02-1=6 | RD3-score02-2=6 | RD3-score02-3=

| RD3-seed03= | RD3-team03=USA M Oudin CHN S Zhang | RD3-score03-1=1 | RD3-score03-2=1 | RD3-score03-3= | RD3-seed04=2 | RD3-team04=RSA N Grandin CZE V Uhlířová | RD3-score04-1=6 | RD3-score04-2=6 | RD3-score04-3=

| RD4-seed01=4 | RD4-team01=UZB A Amanmuradova TPE C-j Chuang | RD4-score01-1=6 | RD4-score01-2=5 | RD4-score01-3=[10] | RD4-seed02=2 | RD4-team02=RSA N Grandin CZE V Uhlířová | RD4-score02-1=4 | RD4-score02-2=7 | RD4-score02-3=[2]

References

Main Draw

Info: Wikipedia Source

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