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2010 UniCredit Czech Open – Doubles
ESP David Marrero AHO Jean-Julien Rojer
Main article: 2010 UniCredit Czech Open
Johan Brunström and Jean-Julien Rojer were the defending champions, but Marcel Granollers and David Marrero defeated them 3–6, 6–4, [10–6] in the final.
Seeds
- SWE Johan Brunström / AHO Jean-Julien Rojer (final)
- ESP Marcel Granollers / ESP David Marrero (champions)
- GER Philipp Marx / SVK Igor Zelenay (semifinals)
- CZE Leoš Friedl / CZE David Škoch (quarterfinals)
Draw
Draw
| RD1-seed01=1 | RD1-team01=SWE J Brunström AHO J-J Rojer | RD1-score01-1=6 | RD1-score01-2=7 | RD1-score01-3= | RD1-seed02= | RD1-team02=KAZ A Golubev KAZ Y Schukin | RD1-score02-1=4 | RD1-score02-2=63 | RD1-score02-3=
| RD1-seed03= | RD1-team03=RSA J Coetzee RSA R de Voest | RD1-score03-1=6 | RD1-score03-2=65 | RD1-score03-3=[10] | RD1-seed04= | RD1-team04=POL T Bednarek POL M Kowalczyk | RD1-score04-1=3 | RD1-score04-2=7 | RD1-score04-3=[7]
| RD1-seed05=4 | RD1-team05=CZE L Friedl CZE D Škoch | RD1-score05-1=6 | RD1-score05-2=7 | RD1-score05-3= | RD1-seed06= | RD1-team06=POR R Machado ESP D Muñoz-De La Nava | RD1-score06-1=3 | RD1-score06-2=64 | RD1-score06-3=
| RD1-seed07= | RD1-team07=USA J Cerretani CAN A Shamasdin | RD1-score07-1=w/o | RD1-score07-2= | RD1-score07-3= | RD1-seed08= | RD1-team08=BEL C Rochus BEL O Rochus | RD1-score08-1= | RD1-score08-2= | RD1-score08-3=
| RD1-seed09= | RD1-team09=THA Sa Ratiwatana THA So Ratiwatana | RD1-score09-1=2 | RD1-score09-2=2 | RD1-score09-3= | RD1-seed10=WC | RD1-team10=CZE J Pospíšil CZE J Vaněk | RD1-score10-1=6 | RD1-score10-2=6 | RD1-score10-3=
| RD1-seed11=WC | RD1-team11=CZE R Rumler CZE R Urbanek | RD1-score11-1=7 | RD1-score11-2=3 | RD1-score11-3=[4] | RD1-seed12=3 | RD1-team12=GER P Marx SVK I Zelenay | RD1-score12-1=63 | RD1-score12-2=6 | RD1-score12-3=[10]
| RD1-seed13=WC | RD1-team13=CZE M Jaloviec CZE M Konečný | RD1-score13-1=3 | RD1-score13-2=1 | RD1-score13-3= | RD1-seed14= | RD1-team14=IND S Devvarman PHI TC Huey | RD1-score14-1=6 | RD1-score14-2=6 | RD1-score14-3=
| RD1-seed15= | RD1-team15=ESP A Martín ESP A Ramos-Viñolas | RD1-score15-1=2 | RD1-score15-2=2 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=ESP M Granollers ESP D Marrero | RD1-score16-1=6 | RD1-score16-2=6 | RD1-score16-3=
| RD2-seed01=1 | RD2-team01=SWE J Brunström AHO J-J Rojer | RD2-score01-1=7 | RD2-score01-2=1 | RD2-score01-3=[10] | RD2-seed02= | RD2-team02=RSA J Coetzee RSA R de Voest | RD2-score02-1=64 | RD2-score02-2=6 | RD2-score02-3=[5]
| RD2-seed03=4 | RD2-team03=CZE L Friedl CZE D Škoch | RD2-score03-1=5 | RD2-score03-2=6 | RD2-score03-3=[9] | RD2-seed04= | RD2-team04=USA J Cerretani CAN A Shamasdin | RD2-score04-1=7 | RD2-score04-2=2 | RD2-score04-3=[11]
| RD2-seed05=WC | RD2-team05=CZE J Pospíšil CZE J Vaněk | RD2-score05-1=3 | RD2-score05-2=4 | RD2-score05-3= | RD2-seed06=3 | RD2-team06=GER P Marx SVK I Zelenay | RD2-score06-1=6 | RD2-score06-2=6 | RD2-score06-3=
| RD2-seed07= | RD2-team07=IND S Devvarman PHI TC Huey | RD2-score07-1=3 | RD2-score07-2=6 | RD2-score07-3=[3] | RD2-seed08=2 | RD2-team08=ESP M Granollers ESP D Marrero | RD2-score08-1=6 | RD2-score08-2=3 | RD2-score08-3=[10]
| RD3-seed01=1 | RD3-team01=SWE J Brunström AHO J-J Rojer | RD3-score01-1=7 | RD3-score01-2=7 | RD3-score01-3= | RD3-seed02= | RD3-team02=USA J Cerretani CAN A Shamasdin | RD3-score02-1=64 | RD3-score02-2=5 | RD3-score02-3=
| RD3-seed03=3 | RD3-team03=GER P Marx SVK I Zelenay | RD3-score03-1=2 | RD3-score03-2=2 | RD3-score03-3= | RD3-seed04=2 | RD3-team04=ESP M Granollers ESP D Marrero | RD3-score04-1=6 | RD3-score04-2=6 | RD3-score04-3=
| RD4-seed01=1 | RD4-team01=SWE J Brunström AHO J-J Rojer | RD4-score01-1=6 | RD4-score01-2=4 | RD4-score01-3=[6] | RD4-seed02=2 | RD4-team02=ESP M Granollers ESP D Marrero | RD4-score02-1=3 | RD4-score02-2=6 | RD4-score02-3=[10]
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