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2009 ATP Studena Croatia Open Umag – Doubles
SVK Michal Mertiňák AHO Jean-Julien Rojer Main article: 2009 ATP Studena Croatia Open Umag
Michal Mertiňák and Petr Pála were the defending champions, but Pala chose not to compete. Mertiňák partnered with František Čermák, and won in the final over Johan Brunström and Jean-Julien Rojer, 6–4, 6–4.
Seeds
- CZE František Čermák / SVK Michal Mertiňák (champions)
- SWE Johan Brunström / AHO Jean-Julien Rojer (final)
- CZE David Škoch / SVK Igor Zelenay (first round)
- AUT Julian Knowle / AUT Jürgen Melzer (quarterfinals)
Draw
Draw
| RD1-seed01=1 | RD1-team01=CZE F Čermák SVK M Mertiňák | RD1-score01-1=4 | RD1-score01-2=7 | RD1-score01-3=[10] | RD1-seed02= | RD1-team02=UKR S Stakhovsky CRO L Zovko | RD1-score02-1=6 | RD1-score02-2=5 | RD1-score02-3=[5] | RD1-seed03= | RD1-team03=ARG B Dabul ARG S Roitman | RD1-score03-1=6 | RD1-score03-2=77 | RD1-score03-3= | RD1-seed04= | RD1-team04=GBR J Delgado GBR J Murray | RD1-score04-1=1 | RD1-score04-2=65 | RD1-score04-3= | RD1-seed05=4 | RD1-team05=AUT J Knowle AUT J Melzer | RD1-score05-1=3 | RD1-score05-2=6 | RD1-score05-3=[10] | RD1-seed06= | RD1-team06=AUT D Köllerer BEL C Rochus | RD1-score06-1=6 | RD1-score06-2=4 | RD1-score06-3=[2] | RD1-seed07=WC | RD1-team07=CRO I Dodig CRO I Ljubičić | RD1-score07-1=4 | RD1-score07-2=2 | RD1-score07-3= | RD1-seed08= | RD1-team08=URU P Cuevas ARG M González | RD1-score08-1=6 | RD1-score08-2=6 | RD1-score08-3= | RD1-seed09= | RD1-team09=ARG JI Chela ESP R Ramírez Hidalgo | RD1-score09-1=3 | RD1-score09-2=3 | RD1-score09-3= | RD1-seed10= | RD1-team10=ESP D Gimeno Traver ESP M Granollers | RD1-score10-1=6 | RD1-score10-2=6 | RD1-score10-3= | RD1-seed11= | RD1-team11=USA J Cerretani USA T Rettenmaier | RD1-score11-1=7 | RD1-score11-2=4 | RD1-score11-3=[12] | RD1-seed12=3 | RD1-team12=CZE D Škoch SVK I Zelenay | RD1-score12-1=5 | RD1-score12-2=6 | RD1-score12-3=[10] | RD1-seed13=WC | RD1-team13=SRB M Djokovic SRB N Djokovic | RD1-score13-1=0 | RD1-score13-2=5 | RD1-score13-3= | RD1-seed14= | RD1-team14=ITA F Fognini ITA P Starace | RD1-score14-1=6 | RD1-score14-2=7 | RD1-score14-3= | RD1-seed15= | RD1-team15=ITA S Bolelli ITA A Seppi | RD1-score15-1=3 | RD1-score15-2=4 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=SWE J Brunström AHO J-J Rojer | RD1-score16-1=6 | RD1-score16-2=6 | RD1-score16-3= | RD2-seed01=1 | RD2-team01=CZE F Čermák SVK M Mertiňák | RD2-score01-1=6 | RD2-score01-2=4 | RD2-score01-3=[12] | RD2-seed02= | RD2-team02=ARG B Dabul ARG S Roitman | RD2-score02-1=1 | RD2-score02-2=6 | RD2-score02-3=[10] | RD2-seed03=4 | RD2-team03=AUT J Knowle AUT J Melzer | RD2-score03-1=4 | RD2-score03-2=1 | RD2-score03-3= | RD2-seed04= | RD2-team04=URU P Cuevas ARG M González | RD2-score04-1=6 | RD2-score04-2=6 | RD2-score04-3= | RD2-seed05= | RD2-team05=ESP D Gimeno Traver ESP M Granollers | RD2-score05-1=6 | RD2-score05-2=6 | RD2-score05-3= | RD2-seed06= | RD2-team06=USA J Cerretani USA T Rettenmaier | RD2-score06-1=4 | RD2-score06-2=3 | RD2-score06-3= | RD2-seed07= | RD2-team07=ITA F Fognini ITA P Starace | RD2-score07-1=65 | RD2-score07-2=66 | RD2-score07-3= | RD2-seed08=2 | RD2-team08=SWE J Brunström AHO J-J Rojer | RD2-score08-1=77 | RD2-score08-2=78 | RD2-score08-3= | RD3-seed01=1 | RD3-team01=CZE F Čermák SVK M Mertiňák | RD3-score01-1=6 | RD3-score01-2=3 | RD3-score01-3=[10] | RD3-seed02= | RD3-team02=URU P Cuevas ARG M González | RD3-score02-1=3 | RD3-score02-2=6 | RD3-score02-3=[8] | RD3-seed03= | RD3-team03=ESP D Gimeno Traver ESP M Granollers | RD3-score03-1=3 | RD3-score03-2=3 | RD3-score03-3= | RD3-seed04=2 | RD3-team04=SWE J Brunström AHO J-J Rojer | RD3-score04-1=6 | RD3-score04-2=6 | RD3-score04-3= | RD4-seed01=1 | RD4-team01=CZE F Čermák SVK M Mertiňák | RD4-score01-1=6 | RD4-score01-2=6 | RD4-score01-3= | RD4-seed02=2 | RD4-team02=SWE J Brunström AHO J-J Rojer | RD4-score02-1=4 | RD4-score02-2=4 | RD4-score02-3=
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