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2007 ASB Classic – Doubles
ARG Paola Suárez IND Shikha Uberoi Main article: 2007 ASB Classic
Elena Likhovtseva and Vera Zvonareva were the defending champions, but neither chose to participate this year.
Janette Husárová and Paola Suárez won the title, defeating Hsieh Su-wei and Shikha Uberoi 6–0, 6–2 in the final.
Seeds
- SVK Janette Husárová / ARG Paola Suárez (champions)
- ARG Gisela Dulko / USA Meilen Tu (first round; retired due to Dulko's right quad strain)
- GRE Eleni Daniilidou / GER Jasmin Wöhr (semifinals)
- POL Marta Domachowska / CRO Jelena Kostanić (first round)
Draw
Draw
| RD1-team01=SVK J Husárová ARG P Suárez | RD1-seed01=1 | RD1-score01-1=6 | RD1-score01-2=6 | RD1-score01-3= | RD1-team02=NZL M Erakovic ITA S Errani | RD1-seed02=WC | RD1-score02-1=1 | RD1-score02-2=2 | RD1-score02-3= | RD1-team03=FRA É Loit HUN Á Szávay | RD1-seed03= | RD1-score03-1=6 | RD1-score03-2=6 | RD1-score03-3= | RD1-team04=CHN C Ji CHN T Li | RD1-seed04= | RD1-score04-1=4 | RD1-score04-2=4 | RD1-score04-3= | RD1-team05=GRE E Daniilidou GER J Wöhr | RD1-seed05=3 | RD1-score05-1=77 | RD1-score05-2=2 | RD1-score05-3=6 | RD1-team06=TPE C-w Chan CZE V Uhlířová | RD1-seed06= | RD1-score06-1=65 | RD1-score06-2=6 | RD1-score06-3=3 | RD1-team07=CZE E Birnerová USA J Craybas | RD1-seed07= | RD1-score07-1=5 | RD1-score07-2=3 | RD1-score07-3= | RD1-team08=SRB J Janković SLO T Križan | RD1-seed08= | RD1-score08-1=7 | RD1-score08-2=6 | RD1-score08-3= | RD1-team09=CHN S Sun CHN T Sun | RD1-seed09= | RD1-score09-1=7 | RD1-score09-2=6 | RD1-score09-3= | RD1-team10=ITA R Oprandi GER J Schruff | RD1-seed10= | RD1-score10-1=5 | RD1-score10-2=0 | RD1-score10-3= | RD1-team11=NZL L Baker AUS N Kriz | RD1-seed11= | RD1-score11-1=3 | RD1-score11-2=6 | RD1-score11-3=6 | RD1-team12=POL M Domachowska CRO J Kostanić | RD1-seed12=4 | RD1-score12-1=6 | RD1-score12-2=2 | RD1-score12-3=3 | RD1-team13=USA L Granville USA C Gullickson | RD1-seed13= | RD1-score13-1=6 | RD1-score13-2=6 | RD1-score13-3= | RD1-team14=RUS E Bychkova GER M Müller | RD1-seed14= | RD1-score14-1=2 | RD1-score14-2=3 | RD1-score14-3= | RD1-team15=TPE S-w Hsieh IND S Uberoi | RD1-seed15= | RD1-score15-1=1 | RD1-score15-2= | RD1-score15-3= | RD1-team16=ARG G Dulko USA M Tu | RD1-seed16=2 | RD1-score16-1=2 | RD1-score16-2=r | RD1-score16-3= | RD2-team01=SVK J Husárová ARG P Suárez | RD2-seed01=1 | RD2-score01-1=6 | RD2-score01-2=6 | RD2-score01-3= | RD2-team02=FRA É Loit HUN Á Szávay | RD2-seed02= | RD2-score02-1=2 | RD2-score02-2=1 | RD2-score02-3= | RD2-team03=GRE E Daniilidou GER J Wöhr | RD2-seed03=3 | RD2-score03-1=6 | RD2-score03-2=6 | RD2-score03-3= | RD2-team04=SRB J Janković SLO T Križan | RD2-seed04= | RD2-score04-1=2 | RD2-score04-2=3 | RD2-score04-3= | RD2-team05=CHN S Sun CHN T Sun | RD2-seed05= | RD2-score05-1=7 | RD2-score05-2=6 | RD2-score05-3= | RD2-team06=NZL L Baker AUS N Kriz | RD2-seed06= | RD2-score06-1=5 | RD2-score06-2=2 | RD2-score06-3= | RD2-team07=USA L Granville USA C Gullickson | RD2-seed07= | RD2-score07-1=5 | RD2-score07-2=2 | RD2-score07-3= | RD2-team08=TPE S-w Hsieh IND S Uberoi | RD2-seed08= | RD2-score08-1=7 | RD2-score08-2=6 | RD2-score08-3= | RD3-team01=SVK J Husárová ARG P Suárez | RD3-seed01=1 | RD3-score01-1=6 | RD3-score01-2=7 | RD3-score01-3= | RD3-team02=GRE E Daniilidou GER J Wöhr | RD3-seed02=3 | RD3-score02-1=4 | RD3-score02-2=5 | RD3-score02-3= | RD3-team03=CHN S Sun CHN T Sun | RD3-seed03= | RD3-score03-1= | RD3-score03-2= | RD3-score03-3= | RD3-team04=TPE S-w Hsieh IND S Uberoi | RD3-seed04= | RD3-score04-1=w/o | RD3-score04-2= | RD3-score04-3= | RD4-team01=SVK J Husárová ARG P Suárez | RD4-seed01=1 | RD4-score01-1=6 | RD4-score01-2=6 | RD4-score01-3= | RD4-team02=TPE S-w Hsieh IND S Uberoi | RD4-seed02= | RD4-score02-1=0 | RD4-score02-2=2 | RD4-score02-3=
References
References
- "2007 Auckland - ITF tournament draws". International Tennis Federation (ITF).
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