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2006 Bank of the West Classic – Doubles
ISR Shahar Pe'er ARG Gisela Dulko Main article: 2006 Bank of the West Classic
Cara Black and Rennae Stubbs were the defending champions, but both chose not to compete that year.
Anna-Lena Grönefeld and Shahar Pe'er won the title, defeating Maria Elena Camerin and Gisela Dulko 6–1, 6–4 in the final.
Seeds
- SVK Daniela Hantuchová / JPN Ai Sugiyama (first round)
- CZE Květa Peschke / SLO Katarina Srebotnik (first round)
- GER Anna-Lena Grönefeld / ISR Shahar Pe'er (champions)
- ITA Maria Elena Camerin / ARG Gisela Dulko (finals)
Results
Draw
| RD1-seed01=1 | RD1-team01=SVK D Hantuchová JPN A Sugiyama | RD1-score01-1=3 | RD1-score01-2=4 | RD1-score01-3= | RD1-seed02= | RD1-team02=SCG J Janković IND S Uberoi | RD1-score02-1=6 | RD1-score02-2=6 | RD1-score02-3=
| RD1-seed03= | RD1-team03=RUS A Kudryavtseva UKR T Luzhanska | RD1-score03-1=1 | RD1-score03-2=3 | RD1-score03-3= | RD1-seed04= | RD1-team04=USA B Mattek IND S Mirza | RD1-score04-1=6 | RD1-score04-2=6 | RD1-score04-3=
| RD1-seed05=4 | RD1-team05=ITA ME Camerin ARG G Dulko | RD1-score05-1=6 | RD1-score05-2=6 | RD1-score05-3= | RD1-seed06= | RD1-team06=FRA N Dechy RUS V Zvonareva | RD1-score06-1=0 | RD1-score06-2=2 | RD1-score06-3=
| RD1-seed07=Q | RD1-team07=GEO S Devidze RUS T Panova | RD1-score07-1=1 | RD1-score07-2=1 | RD1-score07-3= | RD1-seed08= | RD1-team08=UKR A Bondarenko UKR K Bondarenko | RD1-score08-1=6 | RD1-score08-2=6 | RD1-score08-3=
| RD1-seed09= | RD1-team09=CAN M Drake CZE N Vaidišová | RD1-score09-1=6 | RD1-score09-2=6 | RD1-score09-3= | RD1-seed10=WC | RD1-team10=RSA K Grant USA L Osterloh | RD1-score10-1=2 | RD1-score10-2=4 | RD1-score10-3=
| RD1-seed11= | RD1-team11=ARG M Díaz Oliva CHN M Yuan | RD1-score11-1=2 | RD1-score11-2=3 | RD1-score11-3= | RD1-seed12=3 | RD1-team12=GER A-L Grönefeld ISR S Pe'er | RD1-score12-1=6 | RD1-score12-2=6 | RD1-score12-3=
| RD1-seed13= | RD1-team13=LAT L Dekmeijere FIN E Laine | RD1-score13-1=63 | RD1-score13-2=5 | RD1-score13-3= | RD1-seed14= | RD1-team14=USA J Craybas USA M Tu | RD1-score14-1=77 | RD1-score14-2=7 | RD1-score14-3=
| RD1-seed15= | RD1-team15=FRA M Bartoli POL M Domachowska | RD1-score15-1=7 | RD1-score15-2=7 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=CZE K Peschke SLO K Srebotnik | RD1-score16-1=5 | RD1-score16-2=5 | RD1-score16-3=
| RD2-seed01= | RD2-team01=SCG J Janković IND S Uberoi | RD2-score01-1=2 | RD2-score01-2=2 | RD2-score01-3= | RD2-seed02= | RD2-team02=USA B Mattek IND S Mirza | RD2-score02-1=6 | RD2-score02-2=6 | RD2-score02-3=
| RD2-seed03=4 | RD2-team03=ITA ME Camerin ARG G Dulko | RD2-score03-1=6 | RD2-score03-2=6 | RD2-score03-3= | RD2-seed04= | RD2-team04=UKR A Bondarenko UKR K Bondarenko | RD2-score04-1=2 | RD2-score04-2=2 | RD2-score04-3=
| RD2-seed05= | RD2-team05=CAN M Drake CZE N Vaidišová | RD2-score05-1=2 | RD2-score05-2=3 | RD2-score05-3= | RD2-seed06=3 | RD2-team06=GER A-L Grönefeld ISR S Pe'er | RD2-score06-1=6 | RD2-score06-2=6 | RD2-score06-3=
| RD2-seed07= | RD2-team07=USA J Craybas USA M Tu | RD2-score07-1=7 | RD2-score07-2=4 | RD2-score07-3=4 | RD2-seed08= | RD2-team08=FRA M Bartoli POL M Domachowska | RD2-score08-1=5 | RD2-score08-2=6 | RD2-score08-3=6
| RD3-seed01= | RD3-team01=USA B Mattek IND S Mirza | RD3-score01-1=4 | RD3-score01-2=3 | RD3-score01-3= | RD3-seed02=4 | RD3-team02=ITA ME Camerin ARG G Dulko | RD3-score02-1=6 | RD3-score02-2=6 | RD3-score02-3=
| RD3-seed03=3 | RD3-team03=GER A-L Grönefeld ISR S Pe'er | RD3-score03-1=4 | RD3-score03-2=7 | RD3-score03-3=78 | RD3-seed04= | RD3-team04=FRA M Bartoli POL M Domachowska | RD3-score04-1=6 | RD3-score04-2=5 | RD3-score04-3=66
| RD4-seed01=4 | RD4-team01=ITA ME Camerin ARG G Dulko | RD4-score01-1=1 | RD4-score01-2=4 | RD4-score01-3= | RD4-seed02=3 | RD4-team02=GER A-L Grönefeld ISR S Pe'er | RD4-score02-1=6 | RD4-score02-2=6 | RD4-score02-3=
References
References
- [http://tennis.quickfound.net/wta_results_2005/stanford_budapest_results_2005.html 'Cara-Rennae capture Stanford']
- "'Groenefeld-Peer win at Stanford'".
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