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2005 Heineken Open – Doubles

GER Michael Kohlmann AUS Todd Perry Main article: 2005 Heineken Open

Mahesh Bhupathi and Fabrice Santoro were the defending champions of the doubles event of the Heineken Open tennis tournament, held in Auckland, New Zealand, but did not participate this year.

Yves Allegro and Michael Kohlmann won in the final 6–4, 7–6(7–4), against Simon Aspelin and Todd Perry.

Seeds

  1. ARG Gastón Etlis / ARG Martín Rodríguez (quarterfinals)
  2. CZE Cyril Suk / CZE Pavel Vízner (quarterfinals)
  3. AUS Paul Hanley / AUS Jordan Kerr (first round)
  4. ARG Martín García / ARG Mariano Hood (semifinals)

Draw

Draw

| RD1-seed01=1 | RD1-team01=ARG G Etlis ARG M Rodríguez | RD1-score01-1=6 | RD1-score01-2=6 | RD1-score01-3= | RD1-seed02=WC | RD1-team02=NZL GD Jones NZL A Thompson | RD1-score02-1=1 | RD1-score02-2=4 | RD1-score02-3=

| RD1-seed03=Alt | RD1-team03=RSA J Coetzee ESP A Martín | RD1-score03-1=66 | RD1-score03-2=5 | RD1-score03-3= | RD1-seed04= | RD1-team04=CHI F González USA J Thomas | RD1-score04-1=78 | RD1-score04-2=7 | RD1-score04-3=

| RD1-seed05=3 | RD1-team05=AUS P Hanley AUS J Kerr | RD1-score05-1=3 | RD1-score05-2=64 | RD1-score05-3= | RD1-seed06= | RD1-team06=USA G Oliver CZE P Pála | RD1-score06-1=6 | RD1-score06-2=77 | RD1-score06-3=

| RD1-seed07= | RD1-team07=SWE S Aspelin AUS T Perry | RD1-score07-1=6 | RD1-score07-2=6 | RD1-score07-3= | RD1-seed08= | RD1-team08=ARG J Acasuso PER L Horna | RD1-score08-1=1 | RD1-score08-2=1 | RD1-score08-3=

| RD1-seed09= | RD1-team09=ARG JI Chela ARG S Prieto | RD1-score09-1=6 | RD1-score09-2=77 | RD1-score09-3= | RD1-seed10=WC | RD1-team10=NZL D King-Turner NZL M Nielsen | RD1-score10-1=4 | RD1-score10-2=64 | RD1-score10-3=

| RD1-seed11= | RD1-team11=ARG A Calleri RSA R Koenig | RD1-score11-1=3 | RD1-score11-2=67 | RD1-score11-3= | RD1-seed12=4 | RD1-team12=ARG M García ARG M Hood | RD1-score12-1=6 | RD1-score12-2=79 | RD1-score12-3=

| RD1-seed13= | RD1-team13=SUI Y Allegro GER M Kohlmann | RD1-score13-1=6 | RD1-score13-2=6 | RD1-score13-3= | RD1-seed14= | RD1-team14=FRA J Benneteau FRA C Saulnier | RD1-score14-1=3 | RD1-score14-2=3 | RD1-score14-3=

| RD1-seed15= | RD1-team15=CZE T Cibulec SVK D Hrbatý | RD1-score15-1=4 | RD1-score15-2=3 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=CZE C Suk CZE P Vízner | RD1-score16-1=6 | RD1-score16-2=6 | RD1-score16-3=

| RD2-seed01=1 | RD2-team01=ARG G Etlis ARG M Rodríguez | RD2-score01-1=5 | RD2-score01-2=64 | RD2-score01-3= | RD2-seed02= | RD2-team02=CHI F González USA J Thomas | RD2-score02-1=7 | RD2-score02-2=77 | RD2-score02-3=

| RD2-seed03= | RD2-team03=USA G Oliver CZE P Pála | RD2-score03-1=2 | RD2-score03-2=1 | RD2-score03-3= | RD2-seed04= | RD2-team04=SWE S Aspelin AUS T Perry | RD2-score04-1=6 | RD2-score04-2=6 | RD2-score04-3=

| RD2-seed05= | RD2-team05=ARG JI Chela ARG S Prieto | RD2-score05-1=713 | RD2-score05-2=65 | RD2-score05-3=4 | RD2-seed06=4 | RD2-team06=ARG M García ARG M Hood | RD2-score06-1=611 | RD2-score06-2=77 | RD2-score06-3=6

| RD2-seed07= | RD2-team07=SUI Y Allegro GER M Kohlmann | RD2-score07-1=78 | RD2-score07-2=3 | RD2-score07-3=77 | RD2-seed08=2 | RD2-team08=CZE C Suk CZE P Vízner | RD2-score08-1=66 | RD2-score08-2=6 | RD2-score08-3=65

| RD3-seed01= | RD3-team01=CHI F González USA J Thomas | RD3-score01-1=4 | RD3-score01-2=4 | RD3-score01-3= | RD3-seed02= | RD3-team02=SWE S Aspelin AUS T Perry | RD3-score02-1=6 | RD3-score02-2=6 | RD3-score02-3=

| RD3-seed03=4 | RD3-team03=ARG M García ARG M Hood | RD3-score03-1=77 | RD3-score03-2=1 | RD3-score03-3=3 | RD3-seed04= | RD3-team04=SUI Y Allegro GER M Kohlmann | RD3-score04-1=64 | RD3-score04-2=6 | RD3-score04-3=6

| RD4-seed01= | RD4-team01=SWE S Aspelin AUS T Perry | RD4-score01-1=4 | RD4-score01-2=64 | RD4-score01-3= | RD4-seed02= | RD4-team02=SUI Y Allegro GER M Kohlmann | RD4-score02-1=6 | RD4-score02-2=77 | RD4-score02-3=

References

References

  1. "2005 Auckland Men's Doubles draw". [[Association of Tennis Professionals]] (ATP).
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