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2005 BCR Open Romania – Doubles


ARG Sebastián Prieto ROU Andrei Pavel Main article: 2005 BCR Open Romania

Lucas Arnold Ker and Mariano Hood were the defending champions, but Arnold Ker did not compete this year. Hood teamed up with Martín García and lost in the quarterfinals to Juan Ignacio Chela and Luis Horna.

José Acasuso and Sebastián Prieto won the title by defeating Victor Hănescu and Andrei Pavel 6–3, 4–6, 6–3 in the final.

Seeds

  1. ARG Martín García / ARG Mariano Hood (quarterfinals)
  2. AUT Julian Knowle / GER Michael Kohlmann (first round)
  3. ARG José Acasuso / ARG Sebastián Prieto (champions)
  4. POL Mariusz Fyrstenberg / POL Marcin Matkowski (quarterfinals)

Draw

Draw

| RD1-seed01=1 | RD1-team01=ARG M García ARG M Hood | RD1-score01-1=6 | RD1-score01-2=56 | RD1-score01-3=6 | RD1-seed02=WC | RD1-team02=ROU V Ioniță ROU R Sabău | RD1-score02-1=1 | RD1-score02-2=68 | RD1-score02-3=2

| RD1-seed03= | RD1-team03=ARG JI Chela PER L Horna | RD1-score03-1=6 | RD1-score03-2=6 | RD1-score03-3= | RD1-seed04= | RD1-team04=GER T Behrend GER A Waske | RD1-score04-1=2 | RD1-score04-2=2 | RD1-score04-3=

| RD1-seed05=3 | RD1-team05=ARG J Acasuso ARG S Prieto | RD1-score05-1=6 | RD1-score05-2=6 | RD1-score05-3= | RD1-seed06= | RD1-team06=RSA J Coetzee RSA C Haggard | RD1-score06-1=4 | RD1-score06-2=4 | RD1-score06-3=

| RD1-seed07= | RD1-team07=GER F Mayer NED R Wassen | RD1-score07-1=6 | RD1-score07-2=67 | RD1-score07-3= | RD1-seed08= | RD1-team08=FRA PH Mathieu BEL R Rochus | RD1-score08-1=4 | RD1-score08-2=51 | RD1-score08-3=

| RD1-seed09= | RD1-team09=ROU V Hănescu ROU A Pavel | RD1-score09-1=6 | RD1-score09-2=67 | RD1-score09-3= | RD1-seed10= | RD1-team10=CZE P Pála CZE D Škoch | RD1-score10-1=4 | RD1-score10-2=53 | RD1-score10-3=

| RD1-seed11= | RD1-team11=ESP N Almagro ESP A Martín | RD1-score11-1=2 | RD1-score11-2=2 | RD1-score11-3= | RD1-seed12=4 | RD1-team12=POL M Fyrstenberg POL M Matkowski | RD1-score12-1=6 | RD1-score12-2=6 | RD1-score12-3=

| RD1-seed13=WC | RD1-team13=ROU I Moldovan ROU G Moraru | RD1-score13-1=6 | RD1-score13-2=6 | RD1-score13-3= | RD1-seed14= | RD1-team14=ARG C Berlocq ARG M Puerta | RD1-score14-1=1 | RD1-score14-2=2 | RD1-score14-3=

| RD1-seed15= | RD1-team15=ITA D Sanguinetti BEL T Vanhoudt | RD1-score15-1=6 | RD1-score15-2=67 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=AUT J Knowle GER M Kohlmann | RD1-score16-1=4 | RD1-score16-2=50 | RD1-score16-3=

| RD2-seed01=1 | RD2-team01=ARG M García ARG M Hood | RD2-score01-1=3 | RD2-score01-2=3 | RD2-score01-3= | RD2-seed02= | RD2-team02=ARG JI Chela PER L Horna | RD2-score02-1=6 | RD2-score02-2=6 | RD2-score02-3=

| RD2-seed03=3 | RD2-team03=ARG J Acasuso ARG S Prieto | RD2-score03-1=6 | RD2-score03-2=6 | RD2-score03-3= | RD2-seed04= | RD2-team04=GER F Mayer NED R Wassen | RD2-score04-1=1 | RD2-score04-2=2 | RD2-score04-3=

| RD2-seed05= | RD2-team05=ROU V Hănescu ROU A Pavel | RD2-score05-1=6 | RD2-score05-2=67 | RD2-score05-3= | RD2-seed06=4 | RD2-team06=POL M Fyrstenberg POL M Matkowski | RD2-score06-1=2 | RD2-score06-2=53 | RD2-score06-3=

| RD2-seed07=WC | RD2-team07=ROU I Moldovan ROU G Moraru | RD2-score07-1=610 | RD2-score07-2=6 | RD2-score07-3= | RD2-seed08= | RD2-team08=ITA D Sanguinetti BEL T Vanhoudt | RD2-score08-1=58 | RD2-score08-2=4 | RD2-score08-3=

| RD3-seed01= | RD3-team01=ARG JI Chela PER L Horna | RD3-score01-1=3 | RD3-score01-2=4 | RD3-score01-3= | RD3-seed02=3 | RD3-team02=ARG J Acasuso ARG S Prieto | RD3-score02-1=6 | RD3-score02-2=6 | RD3-score02-3=

| RD3-seed03= | RD3-team03=ROU V Hănescu ROU A Pavel | RD3-score03-1=6 | RD3-score03-2=6 | RD3-score03-3= | RD3-seed04=WC | RD3-team04=ROU I Moldovan ROU G Moraru | RD3-score04-1=4 | RD3-score04-2=4 | RD3-score04-3=

| RD4-seed01=3 | RD4-team01=ARG J Acasuso ARG S Prieto | RD4-score01-1=6 | RD4-score01-2=4 | RD4-score01-3=6 | RD4-seed02= | RD4-team02=ROU V Hănescu ROU A Pavel | RD4-score02-1=3 | RD4-score02-2=6 | RD4-score02-3=3

References

References

  1. (19 September 2005). "Unseeded Serra Wins 1st Career Title at ATP Bucharest". Tennis-X.
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