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2004 Dubai Tennis Championships – Men's doubles


FRA Fabrice Santoro IND Leander Paes

Leander Paes and David Rikl were the defending champions but only Paes competed that year with Jonas Björkman.

Björkman and Paes lost in the final 6–2, 4–6, 6–4 against Mahesh Bhupathi and Fabrice Santoro.

Seeds

  1. IND Mahesh Bhupathi / FRA Fabrice Santoro (champions)
  2. SWE Jonas Björkman / IND Leander Paes (final)
  3. BAH Mark Knowles / CAN Daniel Nestor (first round)
  4. CZE Martin Damm / CZE Cyril Suk (first round)

Draw

| RD1-seed01=1 | RD1-team01=IND M Bhupathi FRA F Santoro | RD1-score01-1=6 | RD1-score01-2=6 | RD1-score01-3= | RD1-seed02=WC | RD1-team02=UAE M Ghareeb SUI I Heuberger | RD1-score02-1=4 | RD1-score02-2=2 | RD1-score02-3=

| RD1-seed03= | RD1-team03=RUS N Davydenko ESP F López | RD1-score03-1=6 | RD1-score03-2=6 | RD1-score03-3= | RD1-seed04= | RD1-team04=BEL O Rochus RUS M Safin | RD1-score04-1=4 | RD1-score04-2=2 | RD1-score04-3=

| RD1-seed05=4 | RD1-team05=CZE M Damm CZE C Suk | RD1-score05-1=65 | RD1-score05-2=2 | RD1-score05-3= | RD1-seed06= | RD1-team06=CZE P Pála CZE P Vízner | RD1-score06-1=77 | RD1-score06-2=6 | RD1-score06-3=

| RD1-seed07= | RD1-team07=CRO I Ljubičić NED S Schalken | RD1-score07-1=62 | RD1-score07-2=0 | RD1-score07-3= | RD1-seed08= | RD1-team08=CZE T Cibulec CZE L Friedl | RD1-score08-1=77 | RD1-score08-2=6 | RD1-score08-3=

| RD1-seed09=WC | RD1-team09=UAE O Bahrouzyan UAE N Mohammed | RD1-score09-1=1 | RD1-score09-2=3 | RD1-score09-3= | RD1-seed10= | RD1-team10=GER M Kohlmann GER R Schüttler | RD1-score10-1=6 | RD1-score10-2=6 | RD1-score10-3=

| RD1-seed11= | RD1-team11=ESP R Nadal ESP T Robredo | RD1-score11-1=5 | RD1-score11-2=77 | RD1-score11-3=6 | RD1-seed12=3 | RD1-team12=BAH M Knowles CAN D Nestor | RD1-score12-1=7 | RD1-score12-2=64 | RD1-score12-3=1

| RD1-seed13= | RD1-team13=AUS P Hanley SCG N Zimonjić | RD1-score13-1=6 | RD1-score13-2=3 | RD1-score13-3=7 | RD1-seed14= | RD1-team14=SVK D Hrbatý AUT J Knowle | RD1-score14-1=3 | RD1-score14-2=6 | RD1-score14-3=5

| RD1-seed15= | RD1-team15=ZIM W Black ZIM K Ullyett | RD1-score15-1=3 | RD1-score15-2=4 | RD1-score15-3= | RD1-seed16=2 | RD1-team16=SWE J Björkman IND L Paes | RD1-score16-1=6 | RD1-score16-2=6 | RD1-score16-3=

| RD2-seed01=1 | RD2-team01=IND M Bhupathi FRA F Santoro | RD2-score01-1=6 | RD2-score01-2=6 | RD2-score01-3= | RD2-seed02= | RD2-team02=RUS N Davydenko ESP F López | RD2-score02-1=1 | RD2-score02-2=4 | RD2-score02-3=

| RD2-seed03= | RD2-team03=CZE P Pála CZE P Vízner | RD2-score03-1=6 | RD2-score03-2=7 | RD2-score03-3= | RD2-seed04= | RD2-team04=CZE T Cibulec CZE L Friedl | RD2-score04-1=4 | RD2-score04-2=5 | RD2-score04-3=

| RD2-seed05= | RD2-team05=GER M Kohlmann GER R Schüttler | RD2-score05-1=64 | RD2-score05-2=5 | RD2-score05-3= | RD2-seed06= | RD2-team06=ESP R Nadal ESP T Robredo | RD2-score06-1=77 | RD2-score06-2=7 | RD2-score06-3=

| RD2-seed07= | RD2-team07=AUS P Hanley SCG N Zimonjić | RD2-score07-1=3 | RD2-score07-2=6 | RD2-score07-3=3 | RD2-seed08=2 | RD2-team08=SWE J Björkman IND L Paes | RD2-score08-1=6 | RD2-score08-2=3 | RD2-score08-3=6

| RD3-seed01=1 | RD3-team01=IND M Bhupathi FRA F Santoro | RD3-score01-1=6 | RD3-score01-2=77 | RD3-score01-3= | RD3-seed02= | RD3-team02=CZE P Pála CZE P Vízner | RD3-score02-1=1 | RD3-score02-2=64 | RD3-score02-3=

| RD3-seed03= | RD3-team03=ESP R Nadal ESP T Robredo | RD3-score03-1=3 | RD3-score03-2=4 | RD3-score03-3= | RD3-seed04=2 | RD3-team04=SWE J Björkman IND L Paes | RD3-score04-1=6 | RD3-score04-2=6 | RD3-score04-3=

| RD4-seed01=1 | RD4-team01=IND M Bhupathi FRA F Santoro | RD4-score01-1=6 | RD4-score01-2=4 | RD4-score01-3=6 | RD4-seed02=2 | RD4-team02=SWE J Björkman IND L Paes | RD4-score02-1=2 | RD4-score02-2=6 | RD4-score02-3=4

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